64x^2=225

Solution for 64x^2=225 equation:

64x^2=225

We move all terms to the left:

64x^2-(225)=0

a = 64; b = 0; c = -225;
Δ = b2-4ac
Δ = 02-4·64·(-225)
Δ = 57600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{57600}=240$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-240}{2*64}=\frac{-240}{128}
=-1+7/8
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+240}{2*64}=\frac{240}{128}
=1+7/8
$